0.25y^2+2(0.25y)-10+2(5+(-0.25y)+(-0.125)y^2)=0

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Solution for 0.25y^2+2(0.25y)-10+2(5+(-0.25y)+(-0.125)y^2)=0 equation: 


Simplifying
0.25y2 + 2(0.25y) + -10 + 2(5 + (-0.25y) + (-0.125) * y2) = 0

Remove parenthesis around (0.25y)
0.25y2 + 2 * 0.25y + -10 + 2(5 + (-0.25y) + (-0.125) * y2) = 0

Multiply 2 * 0.25
0.25y2 + 0.5y + -10 + 2(5 + (-0.25y) + (-0.125) * y2) = 0
0.25y2 + 0.5y + -10 + (5 * 2 + (-0.25y) * 2 + -0.125y2 * 2) = 0
0.25y2 + 0.5y + -10 + (10 + -0.5y + -0.25y2) = 0

Reorder the terms:
-10 + 10 + 0.5y + -0.5y + 0.25y2 + -0.25y2 = 0

Combine like terms: -10 + 10 = 0
0 + 0.5y + -0.5y + 0.25y2 + -0.25y2 = 0
0.5y + -0.5y + 0.25y2 + -0.25y2 = 0

Combine like terms: 0.5y + -0.5y = 0.0
0.0 + 0.25y2 + -0.25y2 = 0
0.25y2 + -0.25y2 = 0

Combine like terms: 0.25y2 + -0.25y2 = 0.00
0.00 = 0

Solving
0.00 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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